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Multiple Choice Questions

The equation of the circle which passes through the point of intersection of the circle a...........

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The equation of the circle which passes through the point of intersection of the circle $x^{2}+y^{2}-8x-2y+7 =0$ and $x^{2}+y^{2}-4x+10y+8 =0$ and having its centre on y-axis will be

$x^{2}+y^{2}+22x+9 =0$

$x^{2}+y^{2}+22x-9 =0$

x²+y²+22y +9=0

$x^{2}+y^{2}+22y-9 =0$

Explanation:

x²+y²+22y +9=0

By: Swaminath Yadav

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