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Multiple Choice Questions

If x2 ndash a 3 x a 0 has at least one positive root then ........

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If x² –(a-3)x + a =0 has at least one positive root then

$a\epsilon (-\infty.0]\sqcup [9,\infty ]$

$a\epsilon (-\infty.0)\sqcup [7,9 )$

$a\epsilon (-\infty.0)\sqcup [-7,\infty )$

None of these

Explanation:

$a\epsilon (-\infty.0]\sqcup [9,\infty ]$

By: Swaminath Yadav

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