If the roots of the equation x b x c x c x a x a x b 0 are equal then ........

If the roots of the equation (x-b)(x-c) + (x-c)(x-a) + (x-a)(x-b) = 0 are equal, then

a+b+c=0

a+b $\omega$ +c $\omega$ ² =0

a-b+c=0

a+b $\omega$ ² + c $\omega$ =0

a+b $\omega$ +c $\omega$ ?² =0 and a+b $\omega$ ² + c $\omega$ =0

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