The present age of Harish is 8 times the sum of the ages of his two sons at present. After 8 years, his age will be 2 times the sum of the ages of his two sons. The present age of Harish (in years) is :
This questions was previously asked in
CUET General Aptitude Test Previous Year Question Paper (2024)
Explanation:
- Let's define the variables: Let Harish's present age be H and the sum of his sons' present ages be S.
- According to the problem, Harish's age is currently 8 times the sum of his sons' ages:
\[ H = 8S \]
- After 8 years, Harish's age will be \( H + 8 \) and the sons' combined ages will be \( S + 16 \) (since both sons together will be 16 years older in total).
- At that future point, Harish's age will be twice the sons' total ages:
\[ H + 8 = 2(S + 16) \]
- Substituting \( H = 8S \) into the second equation gives us:
\[ 8S + 8 = 2(S + 16) \]
- Solving, we get:
\[ 8S + 8 = 2S + 32 \]
\[ 6S = 24 \]
\[ S = 4 \]
- Substituting back to find Harish's age:
\[ H = 8 \times 4 = 32 \]
- Therefore, the correct answer is Option 2: 32 .
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By: AARTI