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Pipe A can fill a tank in ‘??’ hours. Ratio of efficiency of pipe A to pipe B in filling the tank is 5 : 7. Pipe A remained open for 5 hours and then pipe B is also opened. Both pipe were opened for 2 more hours so tanks is 70% filled. If pipe A is closed now then in what time pipe B will fill the remaining part of tank.
2 hours
2.5 hours
3.5 hours
3 hours
4 hours
Let pipe A and B can fill 5x unit per hour and 7x unit per hour respectively Let total capacity of tank be y So, 5x × 5 + (5x + 7x) × 2 = 70 /100 y 25x + 24x = 70 /100 y 490x = 7y ?? = 70?? Remaining part = 70x – 49x = 21x Required time = 21?? /7?? = 3 hour
By: Parvesh Mehta ProfileResourcesReport error
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