Time & distance

Quantitative Aptitude (MTS)

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Indian Economy - Understanding the basics of Indian economic system

If a boy goes from his home to his school at a speed of 40 km/h, he reaches 10 minutes early. If he goes at a speed of 35 km/h,

he reaches 5 minutes late. What will be the time taken for the journey at a speed of 35 km/h?

This questions was previously asked in

SSC MTS 7th July 2022 Shift-3

125 minutes

135 minutes

115 minutes

120 minutes

- The difference in arrival times is 15 minutes (10 minutes early and 5 minutes late).

- These 15 minutes represent the time difference due to the speed change from 40 km/h to 35 km/h.

- Calculate the journey time difference caused by this speed change over a constant distance.

- The journey duration at 35 km/h has the boy arriving 15 minutes later than if he traveled at 40 km/h.

- Time taken at 35 km/h is: \((D/35) \times 60\) (minutes), where D is the distance.

- The correct option equates to the time of arrival when fitting these conditions.

- 120 minutes is the correct journey time at 35 km/h.