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The sum of three numbers is 396. If the ratio between the first and the second number is 7: 11 and that between the second
and the third number is 11 : 15. then the difference between the first and the third number is:
86
94
96
85
- The sum of the three numbers is 396.
- The ratio of the first to the second number is given as 7:11.
- The ratio of the second to the third number is given as 11:15.
- Let's assume the first number is 7x, the second number is 11x, and introduce a new variable y for convenience.
- The second number (11x) relates to the third number as 11y to 15y.
- This implies that 11x = 11y and therefore x = y.
- Thus, the numbers become 7x, 11x, and 15x.
- Their sum: 7x + 11x + 15x = 396
- Solving: 33x = 396, gives x = 12.
- First number is 7x = 84.
- Third number is 15x = 180.
- Difference is 180 - 84 = 96.
- Correct Option: 3 (96).
By: santosh ProfileResourcesReport error
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