80 liters of a mixture of alcohol and water contains 60% alcohol. If 'X' liters of water is added to this mixture, then the
percentage of alcohol in the new mixture becomes 40%. What is the value of X?
This questions was previously asked in
SSC MTS 12th July 2022 Shift-1
Explanation:
- You start with an 80-liter mixture containing 60% alcohol. This means there are 48 liters of alcohol (0.6 x 80 = 48).
- To find the new volume of the mixture after adding water, set the new alcohol percentage to 40%.
- The new mixture will have 48 liters of alcohol and total volume will now be 80 + X due to the added water.
- Set up the equation: (48 / (80 + X)) = 0.4, where 0.4 represents 40%.
- Solving for X gives: 48 = 0.4(80 + X), which simplifies to 48 = 32 + 0.4X, resulting in 16 = 0.4X.
- Solving for X gives X = 40.
- Correct answer is therefore Option 3: 40.
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