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Find the least number of six digits which is exactly divisible by 15, 21 and 28.
100480
100270
100380
100340
L.C.M of 15,21 and 28 = 420
The smallest 6 digits number is 100000.
Now find the multiple of 420 close to 100000.
=> 420*238 = 99960. But this is a 5 digit number.
Add 420 to it so that it can become a 6 digit number and will be divisible by 420.
Required Number = 99960 + 420 = 100380
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