In a vessel, milk and water are in a ratio of 3 : 5. In the second vessel, the milk and water are in the ratio of 3 : 2. In what ratio should these two mixtures be mixed to form a new mixture in which the milk and water are in the ratio 2 : 3?
This questions was previously asked in
RRB Clerk Prelims (14 Aug, 2022 Shift 1)
None of these
Incorrect AnswerExplanation:
To solve the problem, we need to determine the amounts of milk in each vessel first, and then find out how to mix them to get the desired ratio in a new mixture.
- First Vessel:
- Ratio of milk to water is 3:5.
- Milk part = 3/8 of the mixture.
- Second Vessel:
- Ratio of milk to water is 3:2.
- Milk part = 3/5 of the mixture.
To find the required ratio in which these mixtures are to be mixed to achieve a milk to water ratio of 2:3 (which means milk part = 2/5 of the mixture):
- We balance the equation based on the milk content from both vessels to equal the new target mixture.
\[
\frac{3}{8}x + \frac{3}{5}y = \frac{2}{5}(x + y)
\]
- Simplifying the equation leads to:
\[
\frac{3}{8}x + \frac{3}{5}y = \frac{2}{5}x + \frac{2}{5}y
\]
- Solving for x and y gives the mixing ratio as 8:1.
Thus, the option 4 with the ratio 8:1 is the correct one.
Answer: Option 4 - 8 : 1
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By: Parvesh Mehta