Direction: Study the following information carefully and answer the question given below.
E, R, K, S, A and G are six friends who have their birthdays either on 11th or 18th of three different months - March, May and November but not necessarily in the same order. No two persons have a birthday on the same day. R has a birthday on the 18th of the month. E does not have her birthday in the last. Number of persons having birthdays before K is same as the number of persons having birthdays after R . Only two persons have a birthday before G. E has a birthday in a month having 30 days. Not more than two persons have a birthday after S. R and A have their birthdays in different months.
Explanation:
Alright, let's break this puzzle down step by step:
- We’ve got 6 people: E, R, K, S, A, and G.
- Birthdays fall on either 11th or 18th, and the months are March (31 days), May (31 days), and November (30 days).
- R's birthday is on an 18th.
- E's birthday isn’t last. E’s birthday is in a month with 30 days (that’s November).
- The number of people before K is the same as the number after R.
- Only two people have birthdays before G.
- No more than two people after S (so S is close to the end).
- R and A must be in different months.
Here's how it plays out:
1. Find out the order.
- Since E’s in November—the only 30-day month.
- Two people before G: So G is either third (with two before) or G is in the third slot.
- R's birthday is on the 18th and can't be last because E isn’t last (since E is in November, which must be the last or second-to-last month numerically).
- S has at most two after, which puts S at 4th, 5th, or 6th.
2. Balance around K & R.
- People before K = people after R. So K sits 1 earlier than R, or 1 after R; since six people, that must be K-1,R,K+4, or vice versa, balancing the left and right.
3. Plug in months and dates:
- For March, May, November each, there are two slots (11th & 18th), but they can’t share days.
- E must be in November.
- R is not in November (because E is already there).
- A isn’t in same month as R.
4. Process of elimination:
- Since two before G, G is third.
- E in Nov (either fifth or sixth; but can’t be sixth—“E isn’t last”), so E is fifth. So Nov 11 or Nov 18 (but must check).
- S has at most two after—it can be 4/5/6, but E is fifth, so S is fourth.
- R must be after K (to create symmetry, before K = after R).
5. Actual sequence:
A possible order is: X, X, G, S, E, X.
G is third, S fourth, E fifth.
6. Align K and R for symmetry:
- Let's fit K and R. For even symmetry, K-1 people before K, R with equal after. Possible only if R is in third, meaning G = R? G third, but each birthday is unique.
- Try making K=1st, G=3rd, E=5th, S=4th, R=6th, A=2nd.
Positions: 1 2 3 4 5 6
K A G S E R
Now, let's allocate dates and months:
- E: Nov (must be fifth), Nov 11 or 18; S fourth (maybe in May or March).
- R sixth: R must be 18th of either March or May.
- G in third slot—now, since only two before, that fits the clues.
Now, since the question is who has 18th March:
- Only 18th spots left to assign.
- R is not in March or November (E is in Nov, R and A not in same months).
- But G is third, S is fourth, E fifth, R sixth—mapping months/dates:
- K (1): 11 March
- A (2): 11 May
- G (3): 18 March
- S (4): 18 May
- E (5): 11 November
- R (6): 18 November
So, option 2: G has a birthday on 18th March.
Option 2: G is the correct answer.
Here’s the quick takeaway:
- G is the only person whose birthday lines up with March 18th.
- A’s birthday is not on 18th March based on the arrangement above.
- If you went with A, double-check the logic flow above for all slots; everything points to G.
Hope this clarifies it for you!