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What will be largest number which divides 37, 59 and 74 leaving remainder 2, 3 and 4 respectively?
7
8
9
12
Let the divisor be X.
Using the standard identity,
Dividend = (Divisor × Quotient) + Reminder
We have,
37 = (X × Q1) + 2
⇒ (X × Q1) = 35 [Where Q1 is a quotient]
Similarly,
59 = (X × Q2) + 3
⇒ (X × Q2) = 56 [Where Q2 is a quotient]
74 = (X × Q3) + 4
⇒ (X × Q3) = 70 [Where Q3 is a quotient]
Now, since X is the largest number satisfying the given condition, X will be the HCF of 35, 56 and 70.
HCF [35, 56, 70] = 7
Hence, option 1 is the correct answer.
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