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Find the value of √(2x−5)2+2√(x−1)2, if 1 < x < 2
3
2
1
0
√(2x−5)2+2√(x−1)2 =√(5−2x)2+2√(x−1)2−−−−−−−(as1 = (5 - 2x) + 2(x - 1) = 5 - 2x + 2x - 2 = 3 ∴√(2x−5)2+2√(x−1)2=3
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What is the new game given to Maharastra's Ahmednagar district?
Sumati Nagar
Godavarin Nagar
Ahilyanagar
Indiranagar
Maharashtra's Ahmednagar district has now been renamed as Ahilyanagar after the Centre gave nod to the move on Friday, state Minister Radhakrishna Vikhe Patil said, recently.
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