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To win an election, a candidate needs 3/4 of the votes casted. If after 2/3 of the votes have been counted, a candidate has 5/6 of what he needs, then what part of the remaining votes does he still need?

1/8

7/12

1/4

3/8

Explanation:

Let the number of votes casted be x.
Then ,number of votes required to win = 3x/4
Counted votes = 2x/3 ; Uncounted votes = (x − 2x/3) = x/3
Votes won by the candidate = 5/6 of 3x/4 = 5x/8
Remaining votes required = (3x/4−5x/8) = x/8
∴ Required fraction = (x/8)/(x/3) =(x/8 ×3/x) = 3/8

By: Deepak Dawra

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