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A mixture of 40 litres of milk and water contains 10% of water. How much water must be added to make the water 20% in the new mixture?

5 L

8 L

10 L

12 L

Explanation:

To solve this question, we can apply a short trick approach;
Required litres of water = A{(100 – x) – (100 – y)} /(100 – y)
Where,
A is the quantity of mixture = 40 ltrs
x is the initial percent of water = 10%
y is required percent of water = 20%
By the short trick approach, we get
= 40{(100 – 10) – (100 – 20)} / (100 - 20)
= 40 × (90 –80) /80 = 5 L

By: Amit Kumar

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