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Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29 and 34 respectively.

1256

1394

1056

956

Explanation:

Here, (20 – 14) = 6, (25 – 19) = 6, (35 – 29)
= 6 and (40 – 34) = 6.
Required number = (L.C.M. of 20, 25, 35, 40) - 6
∴ Required number = 1400 – 6 = 1394.

By: Amit Kumar

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