Directions : Seven cars M,N,O,P,Q,R and S packed in a field. Car N parked 30 m east of Car M. Car R parked south of car N, and distance between car R & car N, is 5 m more than distance between car M and N. Car O parked such the way that it middle of car M and N, and 20 m North of car of car Q. Distance between car Q and S is 10 m less to distance between car N and Car R. car P parked such way, it is south-west of car S, and 15 m away from both car Q and car R south and West respectively.
If A cleaner start cleaning from car M and and end with car S, and he cleaned all seven car, and all time cleaner turn to right direction when have to moved next car, than what distance covered by him?
- 115 m
- 125 m
- 120 m
- 110 m
Explanation
M -> O -> N -> R -> P -> Q -> S
15+15+35+15+15+25 = 120 m
Hence, option 3 is the correct answer.
Question: 2What is shortest distance between car M and car Q, and car Q is in which direction respect of car M?
- 25 m south-east
- 25 m north-west
- 25 m South
- 25 m north-west
Explanation
MQ = √[(20)2 + (15)2] = 25 south-east
Hence, opton 1 is the correct answer.
Question: 3What is shortest distance between car N and Car S, and also car N is in which direction with respect of car S?
- 25 m north
- 22.35 m North-west
- 22.50 m North-west
- 18.25 m North-west
Explanation
NS = √[(20)^2 + (10)^2] = 22.35 north-east
Hence, otpion 2 is the correct answer.
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By: Amit Kumar