If all the odd digits of each number are decreased by 1 and all the even digits of each number are d...........

Logical Reasoning(IBPS RRB PO) Alpha-Numeric Series

Directions: Study the following numbers carefully and answer the questions given below:
5836 7469 8251 6293 4172

If all the odd digits of each number are decreased by 1 and all the even digits of each number are divided by 2 then the even numbers thus formed are arranged in descending from left to right and on the right of these all odd numbers are arranged in ascending order then which of the following numbers will be in the middle of the sequence?

3186

4172

3182

8251

7469

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Explanation:

We have,
The given sequence = 5836   7469   8251   6293   4172
After subtracting 1 from all the odd digits of each number and dividing all the even digits of each number by 2, we get:
4423   6238   4140   3182   2061
Now, arranging all the even numbers in descending order from left to right, we get:
6238   4140   3182
After arranging all the odd number in ascending order on the right of above numbers, we get:
6238   4140   3182   2061   4423
The, number in the middle of the sequence is ‘3182’.