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If 6 years are subtracted from the present age of Ayush and takes 25% of that then we get the present age of his only son. 4 years ago, his daughter’s age is 7 years more than his son. Sum of daughter’s present age and his wife’s present age is 10 years more than Ayush’s present age then find the present age of Ayush if average of present age of entire family is 30.25 yr?
45 year
50 year
60 year
40 year
36 year
Let’s break it down step by step:
- Start with Ayush’s present age = x.
- His son’s present age: 25% of (Ayush’s age minus 6) ? (x - 6) × 0.25.
- Daughter’s age 4 years ago = (daughter’s present age - 4) = (son’s age then + 7) ? d - 4 = (son’s present age - 4) + 7.
- Daughter+wife = Ayush + 10.
- Family: Ayush, son, daughter, wife. Average is 30.25, so sum = 30.25 × 4 = 121.
Now, set up equations:
1. Son = 0.25(x - 6)
2. Daughter’s age = son’s age + 11 (from the previous equation)
3. Daughter + wife = x + 10, so wife = x + 10 -daughter.
Express all in terms of x:
- Son: 0.25x - 1.5
- Daughter: (0.25x - 1.5) + 11 = 0.25x + 9.5
- Wife: x + 10 - (0.25x + 9.5) = 0.75x + 0.5
Add everyone:
x + (0.25x - 1.5) + (0.25x + 9.5) + (0.75x + 0.5) = 121
x + 0.25x + 0.25x + 0.75x = 2.25x
-1.5 + 9.5 + 0.5 = 8.5
So:
2.25x + 8.5 = 121
2.25x = 112.5
x = 50
So, the answer is option:2 - 50 years.
- Ayush is 50.
- His son is 0.25 × 44 = 11.
- Daughter: 11 + 11 = 22.
- Wife: 50 + 10 - 22 = 38.
- 50 + 11 + 22 + 38 = 121; 121 ÷ 4 = 30.25.
All statements check out. Option 2 is absolutely right.
By: Parvesh Mehta ProfileResourcesReport error
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