Quadratic Equations

Quantitative Aptitude(IBPS PO)

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x³ – 4x² + 3x = 0

7y³ – 23y² + 6y = 0

x<=y

x>y

x>=y

Explanation:

x³ – 4x² + 3x = 0
This gives x(x² – 4x + 3) = 0
⇒ x(x – 3)(x – 1) = 0
⇒ x = 0, 1 or 3
7y³ – 23y² + 6y = 0
⇒y(7y² – 23y + 6) = 0
⇒y(7y – 2)(y – 3) = 0
⇒ y = 0, 2/7 or 3
x>=y

By: Amit Kumar

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