Multiple Choice Questions on tan 20 deg tan 40 deg an 20 deg tan 40 deg ........ for 11th Standard Preparation

Mathematics (11th)

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tan 20° + tan 40° + $\sqrt3$ an 20° tan 40° =

$\frac{1}{\sqrt{3}}$

$\sqrt3$ ?

$-\frac{1}{\sqrt{3}}$

$-\sqrt3$

Explanation:

$\sqrt3$ ?

By: Swaminath Yadav

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