Tap A can fill a tank with water in 10 hrs. Tap B fills the same tank with milk in 12.5 hrs. A man who wanted to fill the tank with the mixture opens tap A first , which already contains 8% milk of its own capacity. After two hours he opened tap B till the tank gets filled completely. In what proportion should he mix this solution with the other one containing water and milk in the ratio 2 : 3, so that the new solution will contain half milk and half water?
Explanation:
Solution:
Total work – 50
a== 5
b== 4
it already contain 8% milk = 4 lit
a—- in 2 hrs = 5*2 = 10 lit water
so, total fill = 14 lit. remain. = 36 lit
done by a+b in 36/9 = 4 hrs
so,water added by a — 4*5 = 20 litre
milk added by b —- 4*4 = 16 litre
so. Total water ==== 10 + 20 = 30 litre
Total milk ===== 4 + 16 === 20 litre
W:M = 3:2
now 3/5______________2/5
____________1/2_______1:1
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By: Pranav Gupta