Problems based on Ages

Quantitative Aptitude (CGL)

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15 years ago the average age of a family of four members was 40 years. Two children were born in this span of 15 years. The present average of the family remains unchanged. Among the two children who were born during the 15 years, if the older child at present is 8 years older than the younger one, what is the ratio of the present age of the older child to the present age of the younger Child?

9:4

7:3

7:6

7:4

Explanation:

15 years ago Total age of a family of four members = 160
Sum of the Present age of a family of four members = 160 + (15*4) = 220
Sum of the Present age of a family of six members = 40*6 = 240
x+x+8 = 20
x=6
present age of the older child to the present age of the younger Child = 14:6 = 7:3

By: Pranav Gupta

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