Problems based on Ages

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One year ago, a father was four times as old as his son. Aner six years his age exceeds twice his son's age by 9 years. The ratio of their present age is?

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CAPF 2017 Paper-1

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9:2

11:3

12 : 5

13 : 4

Explanation:

one year ago F:S => 4:1
After 6 years 2x+9 : x
so
(2x+9-7)/(x-7) = 4/1
2x+2 = 4x-28
x = 15
After 6 years
Son = 15 years
FAther = 39 years
At present
F:S => 33:9 => 11:3

By: Sandeep Dubey

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