Explanation:

Here’s how to analyze the problem:

- There are 5 people (P, Q, R, S, T) and 5 distinct tasks.

- P or Q cannot get Task-1, so Task-1 can only go to R, S, or T (3 choices).

- Task-2 must be given to either R or S (2 choices).

- The rest of the tasks can be assigned to any of the remaining people, as per the restrictions already stated.

Let’s count:

1. For Task-2:

- Two choices: R or S.

2. For each case (assign Task-2 to R or S):

- Suppose Task-2 is assigned to R.

- For Task-1: Can be assigned to S or T (since P and Q are not allowed; R is already fixed on Task-2), so 2 choices.

- Similarly, if Task-2 is assigned to S, Task-1 can go to R or T, also 2 choices.

So both cases give us:

2 (for Task-2) × 2 (for Task-1) = 4

3. The remaining 3 tasks can be assigned to the 3 remaining people in 3! = 6 ways.

Total ways:

4 × 6 = 24

Options:

- 1, 6, 12, 24

Correct Answer: Option 4 – 24