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Find the value of √(2x−5)²+2√(x−1)^2, if 1 < x < 2

3

2

1

0

Explanation:

√(2x−5)²+2√(x−1)²
=√(5−2x)²+2√(x−1)²−−−−−−−(as1 = (5 - 2x) + 2(x - 1)
= 5 - 2x + 2x - 2
= 3
∴√(2x−5)²+2√(x−1)²=3

By: MIRZA SADDAM HUSSAIN

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